It's probability time again. With things you can try at home. Inside your sock draw.

unknown_username

In Response to It's probability time again.:

Edit, I'll do this from home. Later.
Posted by mumsie

what was the probability of that?

unknown_username

Edit, I'll do this from home. Later.

FCHD

If it's a probability question, I'm going for 0.5. With a 0.499999 recurring margin of error.

unknown_username

 Thanks Chris and FCHC and sorry about the false start. I dare not put home event probabilities and likelyhoods here for fear of jinxing them.

I'm starting a probability thread  for fun and to see if I can learn something and perhaps clear some merky poker waters , there is so much I don't know and some great explainers here .

Without further ado. 

I'm going to start with basic stuff and hopefully build up to escape velocity equations that apply to poker scenarios.

We toss two fair coins. 

Assuming the tosses are independent, what's the probability of getting two heads?

gazza127

In Response to Re: It's probability time again.:

 Thanks Chris and FCHC and sorry about the false start. I dare not put home event probabilities and likelyhoods here for fear of jinxing them. I'm starting a probability thread  for fun and to see if I can learn something and perhaps clear some merky poker waters , there is so much I don't know and some great explainers here . Without further ado.  I'm going to start with basic stuff and hopefully build up to escape velocity equations that apply to poker scenarios. We toss two fair coins.  Assuming the tosses are independent, what's the probability of getting two heads?
Posted by mumsie

probably a higher probability on valentines

unknown_username

You just  can't get the students these days

Red_King

In Response to Re: It's probability time again.:

 Thanks Chris and FCHC and sorry about the false start. I dare not put home event probabilities and likelyhoods here for fear of jinxing them. I'm starting a probability thread  for fun and to see if I can learn something and perhaps clear some merky poker waters , there is so much I don't know and some great explainers here . Without further ado.  I'm going to start with basic stuff and hopefully build up to escape velocity equations that apply to poker scenarios. We toss two fair coins.  Assuming the tosses are independent, what's the probability of getting two heads?
Posted by mumsie

When the probability is you are behind, gravitate towards the fold button or you won't escape

Glenelg

1/4  NEXT!

unknown_username

Cheers chaps and chapesses

Cheers Glen, we get there by 0.5 * 0.5 . .

Next 

Six individual socks are sitting in a drawer: 

two red, two blue, and two purple.

The universal sock law applies and you pick a first sock and then anothrr sock from the remaining five. 

Assume the two choices are independent. 

What's the probability you end up with matching socks?

markycash

In Response to Re: It's probability time again. Socks now, but never socks again.:

Cheers chaps and chapesses Cheers Glen, we get there by 0.5 * 0.5 . . Next  Six individual socks are sitting in a drawer:  two red, two blue, and two purple. The universal sock law applies and you pick a first sock and then anothrr sock from the remaining five.  Assume the two choices are independent.  What's the probability you end up with matching socks?
Posted by mumsie

Assuming you were picking in a 'lucky dip' type way

1 in 5 or 20%.

There is 1 remaining sock that matches and 4 that don't.

GELDY

In Response to Re: It's probability time again. Socks now, but never socks again.:

Cheers chaps and chapesses Cheers Glen, we get there by 0.5 * 0.5 . . Next  Six individual socks are sitting in a drawer:  two red, two blue, and two purple. The universal sock law applies and you pick a first sock and then anothrr sock from the remaining five.  Assume the two choices are independent.  What's the probability you end up with matching socks?
Posted by mumsie

zero - by the law of sock dynamics the bayesian principle doesn't apply. Just the same as when you take your socks out of the washing machine and there is always an odd one left over.

scouse_red

In Response to Re: It's probability time again. Socks now, but never socks again.:

Cheers chaps and chapesses Cheers Glen, we get there by 0.5 * 0.5 . . Next  Six individual socks are sitting in a drawer:  two red, two blue, and two purple. The universal sock law applies and you pick a first sock and then anothrr sock from the remaining five.  Assume the two choices are independent.  What's the probability you end up with matching socks?
Posted by mumsie

if you pick a red and a blue one ....... 

that would mean that there was a red and a blue one still left ....... so......

you would have 2 pairs of red and blue and a pair of purple, so strangely enough even by picking odd socks you still have the same........

I think......

ot not  

Red_King

In Response to Re: It's probability time again. Socks now, but never socks again.:

In Response to Re: It's probability time again. Socks now, but never socks again. : Assuming you were picking in a 'lucky dip' type way 1 in 5 or 20%. There is 1 remaining sock that matches and 4 that don't.
Posted by markycash

Would the answer be 1, if you were colour blind?

You'd never know the difference