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Hi 1st post so be gentle. lol
What are the odds of AK and AA on a 6 handed table pre flop? I've hunted and cant find the answer. What I do know is I've met the AA 3 times in 4 touneys on the same day. Managed to dodge one but got done in the others.
What was galling was these were the only hands I'd had and I'd played SOOOO tight, and still got busted out.
Thanks TK. By the way I've learnt loads by watching 865. No limping in for me!!!
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This is equivalent to odds of 1127 to 1.
That's sort of what I thought.
To meet that 3x in quick successsion is pretty unlucky but then I seem to be going through that stage where if there is a one outer for my opponant he gets it and if there are 15 for me I dont. Hey ho!
When dealing the first card, 4 of 52 cards are aces
Then to deal this player another ace, 3 of 51 cards are aces
To deal the second player AK:
The first card is 1 of 2 remaining aces in 50 cards
The second card is 1 of 4 kings in 49 cards
The second player could also be dealt KA so this is why it is multiplied by 2.
This would give the probability of 2 players Heads Up being dealt AA & AK.
There are 30 different ways of dealing two hands to 6 players, so you multiply this by 30 to get the probability of it happening on a 6 handed table.
got to be long odds-on, no offers, etc.
The first hour of any tourney is critical. first hour play AA with caution if you shove all in you will get called by a chancer and he will hit, best to raise pre-flob then raise when flop drops no-matter what drops. if he calls try and check to river if he shoves he has more then likerly hit flush or two pair. you have plenty of time to get your chips back, try to show you had AA and nxt time you raise he will fold, your plan should be to get past the first hour so you can play real poker against good players. some might not agree with this but hay we all have our own game. good luck
No problem.
Mathematically speaking, 30 is the number of permutations (as opposed to combinations) of 2 from 6.
With permutations, the order of the two events matters, with combinations the order is irrelevant.
Let's call the six players at the table A, B, C, D, E & F.
Then player A can have the aces and player B can have the ace & king etc.
The following permutations are possible:
AB AC AD AE AF BC BD BE BF CD CE CF DE DF EF
BA CA DA EA FA CB DB EB FB DC EC FC ED FD FE
That is 30 permutations in all.
There is a relatively simple mathematical formula for working this out for any numbers. Any spreadsheet will also provide permutation and combination functions.
Here endeth the (maths) lesson.
If you ever want to know more, please feel free to ask.
If you ever need anyone to give you the kicking of your life, please feel free to ask me.
If you are dealt AK there are 3 aces left in the pack. So each other individual player at the table has 1/490 (3/50 x 2/49) chance of holding AA, multiply that by the 5 players and you get a 1/98 chance that any one of them is holding AA.
There is also a 1/98 chance that any other player holds KK.
So with AK in your pocket, on average, you will be dominated by AA or KK pre-flop 1 in every 49 times.
In Response to Re: What's the odds?:
3/50*2/49 = 1/408 approx.
Therefore, the odds of someone holding either AA or KK if you hold AK on a 6-seater table are very close to 40 to 1.
See here for more "discussion" relating to this.
Merenovice is having some sort of affair with Carol Vorderman imo
amazing
I can confirm that I'm a big Rachel Riley fan.