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odds of 3 flushes in one hand

edited December 2010 in Poker Chat
Ok i have no idea what happened here anyways whats the odds of 3 flushes all connecting on the river ?


PlayerActionCardsAmountPotBalance Small blind £0.02£0.02£1.50The_Don90Big blind £0.04£0.06£3.96 Your hole cardsJK    Fold     Call £0.04£0.10£10.76 Fold     Call £0.04£0.14£2.51 Call £0.02£0.16£1.48The_Don90Check    Flop  2Q7    Check    The_Don90Check     Check     Check    Turn  Q    Check    The_Don90Check     Check     Check    River  4    Bet £0.04£0.20£1.44The_Don90Raise £0.28£0.48£3.68 Call £0.28£0.76£10.48 Call £0.28£1.04£2.23 Fold    The_Don90ShowJK    Muck35    Muck910   The_Don90WinFlush to the King£0.96 £4.64

Comments

  • edited December 2010
    The probability of three players at a 6-seater table being dealt 2 cards of the same suit, making a flush draw by the turn and hitting it on the river is: 12/51*11/50*10/49*9/48*8/47*20*7/46*6/45*39/44*38/43*6*5/42.

    This is equivalent to odds of: 13,063 to 1.
  • edited December 2010
    cheers mate was a curiosity thing
  • edited December 2010
    In Response to Re: odds of 3 flushes in one hand:
    The probability of three players at a 6-seater table being dealt 2 cards of the same suit, making a flush draw by the turn and hitting it on the river is: 12/51*11/50*10/49*9/48*8/47*20*7/46*6/45*39/44*38/43*6*5/42. This is equivalent to odds of: 13,063 to 1.
    Posted by MereNovice
    Excuse me????? lol

    seems i have a looong way to go before i work out HOW to work out the odds.
    Maybe this is where im going wrong? At the moment im feeling my way through tournys,
    as a side question, where do i pick up this info?
  • edited December 2010
    In Response to Re: odds of 3 flushes in one hand:
    In Response to Re: odds of 3 flushes in one hand : Excuse me????? lol seems i have a looong way to go before i work out HOW to work out the odds. Maybe this is where im going wrong? At the moment im feeling my way through tournys, as a side question, where do i pick up this info?
    Posted by major1962
    I worked it out as follows:

    Player A - 1st card could be anything
    Player A - 2nd card must be one of 12 cards of the same suit from 51 cards remaining (hence 12/51)

    Player B - 1st card must be one of 11 cards of the same suit from 50 cards remaining (hence 11/50)
    Player B - 2nd card must be one of 10 cards of the same suit from 49 cards remaining (hence 10/49)

    Player C - 1st card must be one of 9 cards of the same suit from 48 cards remaining (hence 9/48)
    Player C - 2nd card must be one of 8 cards of the same suit from 47 cards remaining (hence 8/47)

    There are 20 ways of choosing 3 hands from 6 players at the table.

    Then exactly two of the first four community cards need to be of the same suit:

    1st community card can be one of 7 cards of the same suit from 46 cards remaining (hence 7/46)
    2nd community card can be one of 6 cards of the same suit from 45 cards remaining (hence 6/45)
    3rd community card can be one of 39 cards of a different suit from 44 cards remaining (hence 39/44)
    4th community card can be one of 38 cards of a different suit from 43 cards remaining (hence 38/43)

    There are 6 ways of choosing 2 cards from the 4 dealt on the flop and turn.

    River card must be one of 5 cards of the same suit from 42 cards remaining (hence 5/42).

    To get the overall probability you multiply all these numbers together.


    I know that you didn't really want to know but I couldn't help myself.
    It's not really of any use to anyone, obviously.
  • edited December 2010
    In Response to Re: odds of 3 flushes in one hand:
    In Response to Re: odds of 3 flushes in one hand : I worked it out as follows: Player A - 1st card could be anything Player A - 2nd card must be one of 12 cards of the same suit from 51 cards remaining (hence 12/51) Player B - 1st card must be one of 11 cards of the same suit from 50 cards remaining (hence 11/50) Player B - 2nd card must be one of 10 cards of the same suit from 49 cards remaining (hence 10/49) Player C - 1st card must be one of 9 cards of the same suit from 48 cards remaining (hence 9/48) Player C - 2nd card must be one of 8 cards of the same suit from 47 cards remaining (hence 8/47) There are 20 ways of choosing 3 hands from 6 players at the table. Then exactly two of the first four community cards need to be of the same suit: 1st community card can be one of 7 cards of the same suit from 46 cards remaining (hence 7/46) 2nd community card can be one of 6 cards of the same suit from 45 cards remaining (hence 6/45) 3rd community card can be one of 39 cards of a different suit from 44 cards remaining (hence 39/44) 4th community card can be one of 38 cards of a different suit from 43 cards remaining (hence 38/43) There are 6 ways of choosing 2 cards from the 4 dealt on the flop and turn. River card must be one of 5 cards of the same suit from 42 cards remaining (hence 5/42). To get the overall probability you multiply all these numbers together. I know that you didn't really want to know but I couldn't help myself. It's not really of any use to anyone, obviously.
    Posted by MereNovice

    i think ill stick to asking
  • edited December 2010
    more to the point how did you not stack them both :p
  • edited December 2010
    In Response to Re: odds of 3 flushes in one hand:
    more to the point how did you not stack them both :p
    Posted by YOUNG_GUN
    good question, i have no idea, wish one of them re-raised then the other one shoves and it goes all in.
  • edited December 2010
    hindsight is a beautiful thing, fair play to them both for just calling although is likely 1 other has better flush
  • edited December 2010
    Sky Poaker is rigged obv
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