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Playing cash, in the small blind with A,3o - limped in along with four out of the other five players.
Three 3s hit the flop - so big kiss for the poker fairy. But what are the odds of this happening (quading a random card on the flop)?
I made it 19,599-1; (3/50) x (2/49) x (1/48) = 6/117,600 = 1/19,600
My boys book of knowledge says that the odds of flopping a quad with two unpaird cards is 9,802.92-1, which is just around half of that and allows for the fact that either of the two cards could quad on the flop.
I think this is my best ever outcome from the flop, and easily beats the three times I've hit quads on the flop from a pocket pair (at 407-1). But . . . I picked up just 63p (16 BBs) as a result.
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Comments
nice attitude sorry.
The small difference between my calc and the boys book of knowledge answer (it's actually a very good coaching book by Ken Warren) is purely down to rounding the decimals on the probability before it was converted to a fraction.
50/50 ? Hmmm . . . . will have to think about that.
I like it more when people are vigorously representing the cards you've just mucked. You can tell who is the sickest puppy and therefore a good online tell.
Look at it another way . . . let's suppose you play a game with 24 players, where 48 cards are dealt out and where you need one of four outs.. If you only divide by the number of cards left to deal out, then the probability of you hitting an out based on the cards in the deck only would be 4 (outs) divided by 4 (cards left), or 100%, ie a dead certainty. There's a strong probability however that those four cards will have been dealt out to other players - in reality the odds of pulling one of the four outs will be 4/50, 1/12.5 or 11.5-1.