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On the flop;
player 1 has - 2c 2h
player 2 has - Qh Kh
Flop is Tc Th Jh
player 2's outs are;
Ac As Ad - Aces for an Ace high straight
Kc Ks Kd - Kings for 2 pair, Kings and Tens
Qc Qs Qd - Queens for 2 pair, Queens and Tens
Jc Js Jd - Jacks for 2 pair (higher kicker), Jacks and Tens
9c 9s 9d - Nines for a King high straight
Ah 9h - Ace or Nine of hearts for a straight flush
8h 7h 6h 5h 4h 3h - 3-8 of hearts for flush (not the 2 as P1 holds this card)
This is 23 outs, with 2 cards to come.
Each card has 2.2% chance of hitting = 50.6% but there's 2 cards to come which means you double it = 101.2%???
When you put this example into a poker odds calculator, the odds are P1 28.08% - 0.91% - 71.01% P2.
How would you calculate the exact odds of winning a hand like this one?
Using basic logic I'd have thought you'd split each card group like I have done above and for each group you then calculate the re-draw possibilty for the full house, 2 Two's and 2 Ten's. So would this be 8.8% of each of the group's percentage except the straight flush and the 2 pair (it would need to only be 4.4% for the 2pr. as the Ten would also improve player 2.
Am I on the right lines?
I'd also need to include a "blank" turn card (3-8, non-heart), this then adds 2 more outs for P2 for the river.
Help!
Comments
Cant remember but im sure it involves the number 8 lol..
Anyway try googling it, it should be somewhere out there
http://img410.imageshack.us/img410/4051/96109346.jpg
there are 38 cards left in the pack, 23 cards which are good, 15 of these you don't want to see, so that works out about 70-30.
So 51.1% you hit the turn, 8.9% they hit the turn, 40% both miss.
So if you hit the turn, you still need him to miss the river, now 4/44 = 9%
So you hitting the turn and missing the river is 51.1% * 91% = 46.5%
Of course, this is slightly high, as there are combinations where you hit and still don't win, a non-heart J counts as a hit, but following it up with a non-heart Ace and you both have 2 pair, Jacks, Tens and an Ace kicker.
Those 40% you miss the turn, you need to hit the river, now 23/44 = 52.2%
So the odds of that are 20.9%, making a total of 67.4%
Of course, there are more dirty ways for you to win, runner runner pair will counterfeit his pocket 2s
Runner runner tens would be in particular horrible.
If in doubt, just ask PokerStove!
P2 wins 71% post-flop
With a blank on the turn (I used 8s), P2 wins 56.8%
Assuming you magically know for certain what Mr. Villain has, there are 45 cards on the turn.
23/45 as a percentage is 23/45*100, which is the same as 23*(100/45). The 100/45 is the 2.2% you get when counting outs.
But you should look for PokerStove online - great for puzzles like this
That would be 1st card being either a 10 (2/45) followed by a Jack (3/44) =0.3%, but double it, as there are the same times it would come Jack followed by then = 0.6%
1st card being a J (3/45), followed by another Jack (2/44) = 0.3%
=0.9% = 9/990
Good maths stuff!
The way iv been taught is say i have Ac,6c flops comes at 4d.6h,7c
My outs are two more 6s, 11 more clubs, and 3 As so you have 19outs you times tht by 4 which is 72% you then +1 so that takes you to 73% but because you had over 9outs you subtract 9 from your % so 73% - 9= so your End % is 64% so you have 32% of hitting the turn and 32% of hitting the river is 32%
Not sure who taught you, but I hope you didn't pay for that advice!