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Odds question...
This is probably a really stupid question to ask as the answer may get me in alot of trouble.
If I am dealt Ace King at a 6 handed table, what are the fractional odds of any opponent having pocket Kings or pocket aces?
Thanx
Comments
Wakey wakey Vince
PS unless as looney says its Tikay or Phil
I'd say that the odds of another player holding AA or KK if you hold AK on a six seater table are 40 to 1
(i.e. 5 * 2 * 3/50 * 2 /49).
As always, I'm happy to be corrected.
I thought 120/1 was abit low....
So if I have ace king, its a 40/1 shot that someone has me absolutely crushed then.
Thanx, I thought the odds wud be something krazy, 300/1 maybe - which wud make AK unfoldable in my mind, and cost me a fortune. 40/1 is a big eye opener for me.
How about the odds of KK and AA being dealt in the same set of hole cards, 6 handed?
Mght as well ask away while you're awake
(There are 30 ways that six players could hold two hands).
The odds of someone holding KK if someone else has AA aren't quite 1/221 but it's close enough.
So to clarify, if I have AK, its a 40/1 shot that Im gonna be crushed.
And If I have KK, Im gonna be AIPF v AA once every 220 times! - I think I've heard that before and just forgot.
Amzed at the 40/1 tho! Scary!
I'd say roughly 1/221*1/221*5*.2*1/221*1/221*5*.2*1/221*1/221*5*.2.
This would be about 116,507,435,287,320 to 1.
If you just mean each time you got AA (on non-consecutive hands) someone got KK and beat you, then I'd say roughly 1/221*5*.2*1/221*5*.2*1/221*5*.2 which is about 10,793,860 to 1.
p.s remember doh that AK gets beat by any pair and even if you catch the flop with either or both there are many scenario's that will beat you.
check this info out: http://www.pokercheckraise.com/poker_probability.html
Also the odds of being dealt AK are actually 82 to 1.
The odds of being dealt AK offsuit are 110 to 1. (109.5 to 1 to be precise).
When copying statistics from a "crib sheet" it is generally wise to make sure that you do it correctly.
Maybe Im the one who doesnt understand my question....
Can u spell out in your words what question you answered Vince with 40/1?
I swear I have an A level in English.....yet I can never explain myself.
I just wanna know the chances someone holds AA OR KK at 6 handed table, when I have ACE KING
Thats what u answered right?
You explained yourself perfectly - on this occasion ;-)))
I will expand on the answer that I gave because stoneface1 appears unable to grasp it and it may help him to explain why I am definitely wrong.
There are 50 cards left in the deck including 3 aces and 3 kings.
The odds of one other person holding AA or KK is
2 * 5 * 3/50 * 2/49
3/50 is the probability that the first card that a person gets dealt is an ace.
2/49 is the probability that the second card that a person gets dealt is also an ace.
Multiply this by 2 for aces or kings.
Multiply this by 5 because any of the 5 players at the table can get this hand.
This gives the probability as 0.0245 which is approximately 40/1.
If you'd like any further clarification, please let me know.
I thought this a while ago when having a debate with someone.
I think 0.01 equates to 1%
0.10 is 10%?
0.99 is 99%
so 0.0245 = 2.45%?
0.0245 is a fraction and equates to 2.45%.
2.5% isn't quite 40 to 1; it is be 39 to 1 (to be precise). :-)))
Mathematicians generally express probabilities as a fraction.